Đề bài

Tính: a) \(\sqrt {0,04}  + \sqrt {0,25}  + 2,31\); b) \(( - \sqrt {0,09} ) + ( - \sqrt {169} ) + 12,501\); c) \(\dfrac{{\sqrt {49} }}{{\sqrt 4 }} + \dfrac{{\sqrt {225} }}{{\sqrt {144} }} - 3,5\); d) \(( - \sqrt {0,04} ).\sqrt {0,01}  + 12,02\); e) \(\left| {\dfrac{{ - 11}}{3}} \right| + {\left( {\dfrac{{ - 1}}{2}} \right)^2} - \left| {4\dfrac{1}{2} + ( - 3,25)} \right|\); g) \(\left| {\sqrt {169}  - \sqrt {900} } \right| - \left| {\dfrac{{ - 5}}{4}} \right|:{\left( {\dfrac{1}{3} - \dfrac{1}{2}} \right)^2}\).

Lời giải chi tiết

a) \(\sqrt {0,04}  + \sqrt {0,25}  + 2,31 = 0,2 + 0,5 + 2,31 = 0,7 + 2,31 = 3,01\);b) \(( - \sqrt {0,09} ) + ( - \sqrt {169} ) + 12,501 =  - {\rm{ }}0,3 + ( - {\rm{ }}13) + 12,501 =  - {\rm{ 0,799}}\);c) \(\dfrac{{\sqrt {49} }}{{\sqrt 4 }} + \dfrac{{\sqrt {225} }}{{\sqrt {144} }} - 3,5 = \dfrac{7}{2} + \dfrac{{15}}{{12}} - 3,5 = 3,5 + 1,25 - 3,5 = 1,25\);d) \(( - \sqrt {0,04} ).\sqrt {0,01}  + 12,02 =  - {\rm{ }}0,2{\rm{ }}.{\rm{ }}0,1 + 12,02 =  - {\rm{ }}0,02 + 12,02 = 12\);e)\(\begin{array}{l}\left| {\dfrac{{ - 11}}{3}} \right| + {\left( {\dfrac{{ - 1}}{2}} \right)^2} - \left| {4\dfrac{1}{2} + ( - 3,25)} \right| = \dfrac{{11}}{3} + \dfrac{1}{4} - \left| {\dfrac{9}{2} - 3,25} \right|\\ = \dfrac{{11}}{3} + \dfrac{1}{4} - \left| {4,5 - 3,25} \right| = \dfrac{{11}}{3} + \dfrac{1}{4} - \left| {1,25} \right| = \dfrac{{11}}{3} + \dfrac{1}{4} - \dfrac{5}{4}\\ = \dfrac{8}{3}\end{array}\)g) \(\begin{array}{l}\left| {\sqrt {169}  - \sqrt {900} } \right| - \left| {\dfrac{{ - {\rm{ }}5}}{4}} \right|:{\left( {\dfrac{1}{3} - \dfrac{1}{2}} \right)^2} = \left| {13 - 30} \right| - \dfrac{5}{4}:{\left( {\dfrac{{ - {\rm{ }}1}}{6}} \right)^2}\\ = \left| { - {\rm{ }}17} \right| - \dfrac{5}{4}:\dfrac{1}{{36}} = 17 - \dfrac{5}{4}.36 = 17 - 45 =  - {\rm{ }}28\end{array}\)