Đề bài

Tính: a)\(\frac{-1}{2}+\frac{5}{6}+\frac{1}{3}\) b)\(\frac{-3}{8}+\frac{7}{4}- \frac{1}{12}\) c)\(\frac{3}{5}: (\frac{1}{4}. \frac{7}{5})\) d)\(\frac{10}{11}+\frac{4}{11}: 4 - \frac{1}{8}\)

Lời giải chi tiết

 a)\(\frac{-1}{2}+\frac{5}{6}+\frac{1}{3}=\frac{-3}{6}+\frac{5}{6} +\frac{2}{6}=\frac{4}{6}=\frac{2}{3}\)b)\(\frac{-3}{8}+\frac{7}{4}- \frac{1}{12}=\frac{-9}{24}+ \frac{42}{24} - \frac{2}{24}=\frac{31}{24}\)c)\(\frac{3}{5}: (\frac{1}{4}.\frac{7}{5})=\frac{3}{5}: \frac{7}{20}= \frac{3}{5}. \frac{20}{7}=\frac{12}{7}\)d)\(\frac{10}{11}+\frac{4}{11}:4-\frac{1}{8}=\frac{10}{11}+ \frac{4}{11}.\frac{1}{4}-\frac{1}{8}=\frac{10}{11}+ \frac{1}{11} - \frac{1}{8}= 1- \frac{1}{8}=\frac{7}{8}\)