Đề bài

Tìm x, biết: a)     x - \(\frac{5}{6}=\frac{1}{2}\) b)    \(\frac{-3}{4} – x = \frac{-7}{12}\)

Lời giải chi tiết

a)     x - \(\frac{5}{6}=\frac{1}{2}\) x = \(\frac{1}{2} +\frac{5}{6}\) x = \(\frac{3}{6}+\frac{5}{6}\) x = \(\frac{8}{6}\) x =\(\frac{4}{3}\) Vậy  x=\(\frac{4}{3}\) b)    \(\frac{-3}{4} – x = \frac{-7}{12}\) x  = \(\frac{-3}{4} - \frac{-7}{12}\) x = \(\frac{-3}{4}+\frac{7}{12}\) x  = \(\frac{-9}{12}+\frac{7}{12}\) x  = \(\frac{-2}{12}\) x= \(\frac{-1}{6}\) Vậy x= \(\frac{-1}{6}\)